SOLUTION: Jane left the school and started to bike along the road at a rate of 12 mph. Her friend Sally left the school 10 minutes after Jane, biking on the same road at a rate of 15 mph. Ho

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Jane left the school and started to bike along the road at a rate of 12 mph. Her friend Sally left the school 10 minutes after Jane, biking on the same road at a rate of 15 mph. Ho      Log On

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Question 1141138: Jane left the school and started to bike along the road at a rate of 12 mph. Her friend Sally left the school 10 minutes after Jane, biking on the same road at a rate of 15 mph. How long will it take Sally to catch up with Jane?

Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Jane: 12%2A%281%2F6%29=2miles

Sally: approach rate is 15-12=3mph

Catch up:
3%28miles%2Fhour%29%2Ax%28hours%29=2%2Amiles
x=2%2F3
FORTY MINUTES