Question 1141075: twice carry's age, added to sam's age, gives you a total of 20. if 3 times carry's age is subracted from twice sam's age, the result is 3 times carry's age, increased by 10. how old is each
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! c = Carryy's present age
s = Sam's age
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twice carry's age, added to sam's age, gives you a total of 20.
2c + s = 20
if 3 times carry's age is subtracted from twice sam's age, the result is 3 times carry's age, increased by 10.
2s - 3c = 3c + 10
2s - 3c - 3c = 10
2s - 6c = 10
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multiply the first equation by 2 and rearrange, subtract the above equation
2s + 4c = 40
2s - 6c = 10
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0 + 10c = 30
c = 30/10
c = 3 yrs is Carry's age
Find s
2s - 6(3) = 10
2s = 10 + 18
2s = 28
s = 28/2
s = 14 yrs is Sam's age
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check solution in statement
"if 3 times carry's age is subracted from twice sam's age, the result is 3 times carry's age, increased by 10. "
2(14) - 3(3) = 3(3) + 10
28 - 9 = 9 + 10
28 = 9 + 9 + 10
28 = 28
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