SOLUTION: A business invests $10,000 in a savings account for two years. At the beginning of the second year, an additional $3500 is invested. At the end of the second year, the account ba
Algebra ->
Quadratic Equations and Parabolas
-> SOLUTION: A business invests $10,000 in a savings account for two years. At the beginning of the second year, an additional $3500 is invested. At the end of the second year, the account ba
Log On
Question 114094: A business invests $10,000 in a savings account for two years. At the beginning of the second year, an additional $3500 is invested. At the end of the second year, the account balance is $15,569.75. What was the annual interest rate? Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! Let x be the annual interest rate.
10000+10000x= total amount after 1yr.
x(13500+10000x)+13500+10000x=15569.75
13500x+10000x^2+13500+10000x-15569.75=0
10000x^2+23500x-2069.75=0
x=-2.435, x=.085 (see below)
x=.085 is the only answer for this question because the other is negative.
Annual interest rate is 8.5%
Ed