SOLUTION: I know this is a M1 V1=M2 V2 problem but I can't figgur out how to start it. Calculate the molarity of solutions made by mixing 175 ml of 3.0 M HCL with 115 mL of 6.0 M HCL.

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Question 1140853: I know this is a M1 V1=M2 V2 problem but I can't figgur out how to start it.
Calculate the molarity of solutions made by mixing 175 ml of 3.0 M HCL with 115 mL of 6.0 M HCL.
Found 2 solutions by josgarithmetic, rothauserc:
Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website!
-----But this is not the formula you need in your example.

The formula you actually need is different.

0.175 L of 3.0 M HCl mix with 0.115 L of 6.0 HCl;
Total volume is .

Total moles of HCl:

Resulting Concentration:
MOLAR

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Your formula is, for V in liters and M in molarity

subscript "r" for "resulting mixture"

Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website!
Solution 1 is 175 ml of 3.0 M HCL
:
Solution 2 is 115 ml of 6.0 M HCL
:
Solution 1
:
175/1000 = 0.175 L
:
Moles = molarity * volume
:
Moles = 3 * 0.175 = 0.525
:
Solution 2
:
115/1000 = 0.115 L
:
Moles = 6 * 0.115 = 0.69
:
Sum the two values to get the total number of moles = 0.525 + 0.69 = 1.215 moles of HCL
:
Sum the volumes of solutions to determine the final volume = 0.175 + 0.115 = 0.29 L
:
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Final molarity of the mixed solution = moles / liter = 1.215/0.29 = 4.1897 M
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