SOLUTION: Find a polynomial function with least positive degree and having integral coefficients whose roots are √2 and -4, and whose y-intercept is 16? I have no idea what integral coe

Algebra ->  Linear-equations -> SOLUTION: Find a polynomial function with least positive degree and having integral coefficients whose roots are √2 and -4, and whose y-intercept is 16? I have no idea what integral coe      Log On


   

Question 1140806: Find a polynomial function with least positive degree and having integral coefficients whose roots are √2 and -4, and whose y-intercept is 16?
I have no idea what integral coefficients are and what to do with the roots. :(( I tried looking up similar problems online but I failed to see any.
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
Roots are sqrt%282%29, and -4. Wanting INTEGER coefficients, another root should be -sqrt%282%29.

y=a%28x-sqrt%282%29%29%28x-%28-sqrt%282%29%29%29%28x-%28-4%29%29
-
y=a%28x-sqrt%282%29%29%28x%2Bsqrt%282%29%29%28x%2B4%29
Next, you want to use the given point of the graph, (0, 16), to solve for the leading coefficient, "a".

You will want to finish your function as polynomial in descending order of degree.