SOLUTION: solve for x: 29/2+3log(2x-5)=3
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Question 1140764
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solve for x: 29/2+3log(2x-5)=3
Answer by
t0hierry(194)
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3 - 29/2 = 3 log(2x - 5)
1 - 29/6 = log (2x - 5)
-23/6 = log (2x - 5)
exp(-23/6) = 2x - 5
x = 5/2 + 1/2 exp(-23/6)