SOLUTION: The problem given is ((6y)/(6y-14))/((21)/(9y-21))/((y^2)/(35)) or ((6y)/(6y-14))÷((21)/(9y-21))÷((y^2)/(35)) The question says to divide, and give answers in simplest for

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: The problem given is ((6y)/(6y-14))/((21)/(9y-21))/((y^2)/(35)) or ((6y)/(6y-14))÷((21)/(9y-21))÷((y^2)/(35)) The question says to divide, and give answers in simplest for      Log On


   

Question 1140456: The problem given is
((6y)/(6y-14))/((21)/(9y-21))/((y^2)/(35))
or
((6y)/(6y-14))÷((21)/(9y-21))÷((y^2)/(35))
The question says to divide, and give answers in simplest form.
Thank you in advance

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


((6y)/(6y-14))÷((21)/(9y-21))÷((y^2)/(35))

The form of the expression is A÷B÷C, where each of A, B, and C is a fraction.

(1) perform the divisions in order, left to right
(2) change division of fractions to multiplication of the reciprocals

%286y%2F%286y-14%29%29%2A%28%289y-21%29%2F21%29%2A%2835%2Fy%5E2%29

Factor the common factors out of the binomials....

%286y%2F%282%283y-7%29%29%29%2A%28%283%283y-7%29%29%2F21%29%2A%2835%2Fy%5E2%29

Then simplify by canceling all factors common to both numerator and denominator.