SOLUTION: The greater of two consecutive even integers is more than one-half times the smaller. What are the smallest possible integers?

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Question 1140421: The greater of two consecutive even integers is more than one-half times the smaller. What are the smallest possible integers?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Consecutive even numbers can be represented by x(smaller one) for the first and the next number has to be 2 more than that. So the next even number is x+%2B+2 (greater one).
if the greater of two consecutive even integers is more than one-half times the smaller, we have
x+%2B+2%3E%281%2F2%29x
x+-%281%2F2%29x%3E-2
%281%2F2%29x%3E-2
x%3E-2%2F%281%2F2%29
x%3E-4=> first possible solution for x is -2
then x+%2B+2 (greater one) will be -2+%2B+2=0
the smallest possible integers: -2, 0