SOLUTION: How do i find the equation of a parabola in standard form with the x intercepts of 0 and 630 the y intercept of 0 and the vertex of 315, 630

Algebra ->  Linear-equations -> SOLUTION: How do i find the equation of a parabola in standard form with the x intercepts of 0 and 630 the y intercept of 0 and the vertex of 315, 630      Log On


   

Question 1140388: How do i find the equation of a parabola in standard form with the x intercepts of 0 and 630 the y intercept of 0 and the vertex of 315, 630
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

the equation of a parabola in standard form with the
x intercepts of 0+and 630 => or points (0, 0+) and (630, 0+)
y intercept of 0+=>(0, 0+)
vertex of (315, 630+)
use f+%28x%29+=+a%28x+-+h%29%5E2+%2B+k, where (h, k) is the vertex of the parabola:
plug in coordinates of the vertex and one point given above:
vertex of (315, 630+=(h, k+
and x-intercept (0, 0+
0=+a%280+-+315%29%5E2+%2B+630...solve for a
0=+a%28+-+315%29%5E2+%2B+630
-630=+a%2A99225+
a=-630%2F99225
a=-2%2F315

your equation is:
f+%28x%29+=+-%282%2F315%29%28x+-+315%29%5E2+%2B+630