SOLUTION: Working together, it takes two different sized hoses 30 minutes to fill a small swimming pool. If it takes 40 minutes for the larger hose to fill the swimming pool by itself, how l

Algebra ->  Human-and-algebraic-language -> SOLUTION: Working together, it takes two different sized hoses 30 minutes to fill a small swimming pool. If it takes 40 minutes for the larger hose to fill the swimming pool by itself, how l      Log On


   



Question 1140370: Working together, it takes two different sized hoses 30 minutes to fill a small swimming pool. If it takes 40 minutes for the larger hose to fill the swimming pool by itself, how long will it take the smaller hose to fill the pool on it’s own?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Working together, it takes two different sized hoses 30 minutes to fill a small swimming pool.
If it takes 40 minutes for the longer hose to fill the swimming pool by itself, how long will it take the smaller hose to fill the pool on it’s own?
:
let h = the time required for the small hose to fill the pool (in minutes)
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let the completed job = 1, (a full pool)
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Each will do a fraction of the job, the two fractions add up to 1
30%2F40 + 30%2Fh = 1
multiply equation by 40h, cancel the denominators and you have
30h + 40(30) = 40h
1200 = 40h - 30h
1200 = 10h
h = 1200/10
h = 120 min for the smaller hose
:
:
see if that checks out
30%2F40 + 30%2F120 = 1