SOLUTION: A bag contains 7 red apples and 4 yellow apples. 4 apples are selected at random. Find the probability of selecting 1 red applenothing and 3 yellow apples.
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-> SOLUTION: A bag contains 7 red apples and 4 yellow apples. 4 apples are selected at random. Find the probability of selecting 1 red applenothing and 3 yellow apples.
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Question 1140308: A bag contains 7 red apples and 4 yellow apples. 4 apples are selected at random. Find the probability of selecting 1 red applenothing and 3 yellow apples. Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! 1 red apple and 3 yellow apples
11C4 are number of ways to select 4=330 possibilities.
7C1*4C3=7*4=28 ways to choose 1 red and 4 yellow
probability is 28/330=0.0848
(7/11)(4/10)(3/9)(2/8)=one way this can happen=168/7920
four ways the red may appear, so total is 672/7920=0.0848
