SOLUTION: A box contains $7.55 in nickels, dimes, and quarters. There are 44 coins in all, and the sum of the numbers of nickels and dimes is 2 less than the number of quarters. How many coi
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Question 1140275: A box contains $7.55 in nickels, dimes, and quarters. There are 44 coins in all, and the sum of the numbers of nickels and dimes is 2 less than the number of quarters. How many coins of each kind are there? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! nickels=x
dimes=y
quarters=z
x+y+z=44
x+y=z-2
so z-2+z=44
2z=46
z=23 quarters (5.75)ANSWER
x nickels
23-x dimes
.05x+.10(23-x)=1.80 (the difference between 5.75 and 7.55)
.05X+2.30-.10X=1.80
-.05X=-0.50
x=10 nickels (0.50) ANSWER
23-x=13 dimes (1.30)ANSWER
