SOLUTION: If you throw a ball straight up from a rooftop 160 feet high with an initial speed of 48 feet per second, then the formula h=-16t^2+48t+160 describes the ball's height h fee
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-> SOLUTION: If you throw a ball straight up from a rooftop 160 feet high with an initial speed of 48 feet per second, then the formula h=-16t^2+48t+160 describes the ball's height h fee
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Question 1140224: If you throw a ball straight up from a rooftop 160 feet high with an initial speed of 48 feet per second, then the formula h=-16t^2+48t+160 describes the ball's height h feet above the ground, t seconds after you released it. The ball misses the rooftop and eventually strikes the ground.
A) What is the height of the ball one second after you release it?
Solution:Find
the value of h in the formula h=−16t^2+48t+160 when t = 1.
h =_____feet
the answer i got was 192
b) How long will it take the ball th hit the ground?
Solution:Find the value of t in the formula h=−16t^2+48t+160
when h = 0.
It will take _____ seconds for the ball th hit the ground.
the answer i got was 5 Answer by greenestamps(13200) (Show Source):
