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Read attentively on how I re-formulated your original post to make sense.
    in how many distinct ways can a  5-symbol  password be made using 
    two letters and three
 5-symbol  password be made using 
    two letters and three  digits if no repeats are allowed?
 digits if no repeats are allowed? 
Solution
You have 5 symbols : 5 = 2 letters + 3 digits,
so 5! = 120 permutations are possible.    ANSWER
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Two different readings and interpretations of your condition are possible.
1.    Two  fixed  letters and  3  fixed  digits are allowed / (are used).
    
    It is exactly that reading and interpretation that I used in my solution.
and
2.    Any two letters of the English alphabet and any  3  digits of ten digits are allowed.
Then the solution should be different.
But just the fact that two different interpretations are possible makes this formulation  DEFECTIVE.