SOLUTION: a parking lot has a perimeter of 16000ft. the width is 40ft more than twice the length. find the dimensions. please show your work here's what I have done p=2l+2w=16000 l+w

Algebra ->  Trigonometry-basics -> SOLUTION: a parking lot has a perimeter of 16000ft. the width is 40ft more than twice the length. find the dimensions. please show your work here's what I have done p=2l+2w=16000 l+w      Log On


   

Question 1140088: a parking lot has a perimeter of 16000ft. the width is 40ft more than twice the length. find the dimensions.
please show your work
here's what I have done
p=2l+2w=16000
l+w=8000
l=2w+8000
2w+40+w=8000
3w=7960
7960/3=2653.3
l=2(2653)+8000
l=13306
Found 2 solutions by josgarithmetic, MathLover1:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
p=2L%2B2w
p%2F2=L%2Bw
-
w=2L%2B40, width is 40ft more than twice the length.
-
16000%2F2=L%2B%282L%2B40%29
8000=L%2B2L%2B40
.
.
L=2653%261%2F3
-
return again to w=2L+40 and evaluate width.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

a parking lot has a perimeter of P=16000ft.
=>P=2%28L%2BW%29 where L is length and W width
2%28L%2BW%29=16000ft
if the width is 40ft more than twice the length, we have
W=2L%2B40ft
then
2%28L%2B2L%2B40ft%29=16000ft
L%2B2L%2B40ft=16000ft%2F2
3L%2B40ft=8000ft
3L=8000ft-40ft
3L=7960ft
L=7960ft%2F3
L=2653.3ft

W=2L%2B40ft
W=2%2A2653.3ft%2B40ft
W=5306.6ft%2B40ft
W=5346.6ft

check:
2%282653.3ft%2B5346.6ft%29=16000ft
2%287999.9ft%29=16000ft
15999.8ft=16000ft
16000ft=16000ft