SOLUTION: NASA launches a rocket at
t
=
0
t=0
seconds. Its height, in meters above sea-level, in terms of time is given by
h
=
−
4.9
t
2
+
199
t
+
381
h=-4.9t2+199t+381
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: NASA launches a rocket at
t
=
0
t=0
seconds. Its height, in meters above sea-level, in terms of time is given by
h
=
−
4.9
t
2
+
199
t
+
381
h=-4.9t2+199t+381
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Question 1140036: NASA launches a rocket at
t
=
0
t=0
seconds. Its height, in meters above sea-level, in terms of time is given by
h
=
−
4.9
t
2
+
199
t
+
381
h=-4.9t2+199t+381
.
How high is the rocket after 4 seconds?
How high was the rocket when it was initially launched? Found 2 solutions by ikleyn, Alan3354:Answer by ikleyn(52887) (Show Source):
