SOLUTION: Assume that women's weights are normally distributed with a mean given by μ=143 lb and a standard deviation given by σ=29 lb.
(A) If 3 women are randomly selected, find the prob
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-> SOLUTION: Assume that women's weights are normally distributed with a mean given by μ=143 lb and a standard deviation given by σ=29 lb.
(A) If 3 women are randomly selected, find the prob
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Question 1140006: Assume that women's weights are normally distributed with a mean given by μ=143 lb and a standard deviation given by σ=29 lb.
(A) If 3 women are randomly selected, find the probability that they have a mean weight above 176
(B) If 92 women are randomly selected, find the probability that they have a mean weight above 176
You can put this solution on YOUR website! z>(x bar-mean)/sigma/sqrt(n)
>33*sqrt(3)/29=1.97
probability z>1.97 is 0.0244
with 92, it is sqrt (92)
probability is z>11.21 which is 0.
