SOLUTION: hello tutors and tks for all your help...i'm a layman in math and learning on my own. So ,i have this question for you.log base 2 to the exp.logbase3 to the exp.logbase4to the exp(

Algebra ->  Exponents -> SOLUTION: hello tutors and tks for all your help...i'm a layman in math and learning on my own. So ,i have this question for you.log base 2 to the exp.logbase3 to the exp.logbase4to the exp(      Log On


   

Question 1139971: hello tutors and tks for all your help...i'm a layman in math and learning on my own. So ,i have this question for you.log base 2 to the exp.logbase3 to the exp.logbase4to the exp(x)=0 when i worked it out I got 64 for an answer.however I didn't have the ability to check this answer out...Can i have a step by step answer to learn to check out my answer...Thanks to all.
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Your description of the equation is nonsense; but it is clear what the equation is supposed to be:

"log base 2 of (log base 3 of (log base 4 of x))) = 0"

log%282%2C%28log%283%2C%28log%284%28x%29%29%29%29%29%29+=+0

Use the basic definition of logarithms repeatedly to find the value of x.

log%282%2C%28log%283%2C%28log%284%28x%29%29%29%29%29%29+=+0 --> log%283%2C%28log%284%28x%29%29%29%29+=+2%5E0+=+1

log%283%2C%28log%284%28x%29%29%29%29+=+1 --> log%284%28x%29%29+=+3%5E1+=+3

log%284%28x%29%29+=+3 --> x+=+4%5E3+=+64