SOLUTION: Divide 56 into two parts such that three times the first part exceeds one third of the second by 48. The parts are ?

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Question 1139921: Divide 56 into two parts such that three times the first part exceeds one third of the second by 48. The parts are ?
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
system%28x%2By=56%2C3x-%281%2F3%29y=48%29

system%289x-y=144%2Cx%2By=56%29
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