SOLUTION: an airplane has just enough fuel for a 6 hour flight. How far can it fly, round trip, in which during the first leg of the trip, it flies with the wind at 235 miles per hour, and d

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Question 1139755: an airplane has just enough fuel for a 6 hour flight. How far can it fly, round trip, in which during the first leg of the trip, it flies with the wind at 235 miles per hour, and during the return trip, it flies against the wind at 190 miles per hour.
Found 2 solutions by josmiceli, Alan3354:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
It sounds like they are including the effect of
the wind to arrive at their speeds.
Let +d+ = the one-way distance
Let +t+ = time in hrs for 1st leg
+6+-+t+ = time in hrs for 2nd leg
-------------------------------------------
(1) +d+=+235t+
(2) +d+=+190%2A%28+6+-+t+%29+
--------------------------------
+235t+=+190%2A%28+6+-+t+%29+
+235t+=+1140+-+190t+
+425t+=+1140+
+t+=+2.6824+
and
+d+=+235%2A2.6824+
+d+=+630.353+ mi
For the round trip:
+2d+=+1260.706+ mi
----------------------------
check:
(2) +d+=+190%2A%28+6+-+t+%29+
(2) +d+=+190%2A%28+6+-+2.6824+%29+
(2) +d+=+190%2A3.3176+
(2) +d+=+630.344+ mi
error due to rounding off, I think
check the math

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
an airplane has just enough fuel for a 6 hour flight. How far can it fly, round trip, in which during the first leg of the trip, it flies with the wind at 235 miles per hour, and during the return trip, it flies against the wind at 190 miles per hour.
---------
Avg speed of the RT = 2*235*190/(235+190) = ~ 210.1176 mi/hr
d = 6*Agv speed = 1260.7 mi RT
--> 630 miles each way
=================
Check:
630/235 + 630/195 = 5.91 hours
Not 6 due to roundoffs.