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Question 1139502: Last year, at Haven's Pond Car Dealership, for a particular model of BMW, Jeep, and Toyota, one could purchase all three cars for a total of $140,000. This year, due to inflation, the same cars would cost $151,830. The cost of the BMW increased by 8%, the Jeep by 4%, and the Toyota by 10%. If the price of last year's Jeep was $6,000 less than the price of last year's BMW, what was the price of each of the three cars last year? (Round your answers to the nearest integer.)
Answer by greenestamps(13209)   (Show Source):
You can put this solution on YOUR website!
The numbers are ugly enough I don't care to take the time to work the problem all the way through. I'll let you do that.
Here are two basic ways to set up the problem for solving:
(1) 3 variables, 3 equations
b+j+t = 140000 (this year's cost of the BMW, Jeep, and Toyota is $140,000
j = b-6000 (this year the cost of the jeep is $6000 less than the cost of the BMW)
1.08b+1.04j+1.10t = 151,830 (next year's cost of the three, with the given percent increases, is $151,830)
You would probably solve this system by a combination of substitution and elimination....
(2) 1 variable, 1 equation
Let x be the cost of the BMW
Then the cost of the Jeep is x-6000
Then the cost of the Toyota is 140000-(2x-6000) ($140,000 minus the cost of the other two)
Then the equation (still ugly; but easier to solve than the system of 3 equations) is
1.08(x)+1.04(x-6000)+1.10(140000-(2x-6000)) = 151830
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