SOLUTION: Find the average rate of change of f(x) =2x^3 from -4 to 0
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Question 1139374: Find the average rate of change of f(x) =2x^3 from -4 to 0
Need this solved step by step line by line with explanation per line.
Thank you. Found 2 solutions by MathLover1, rothauserc:Answer by MathLover1(20850) (Show Source):
You can put this solution on YOUR website! slope = average rate of change = (f(b) - f(a)) / (b - a), where b is the upper bound of the interval and a is the lower bound of the interval
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a = -4, b = 0
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f(0) = 2 * 0^3 = 0
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f(-4) = 2 * (-4)^3 = -128
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average rate of change = (0 - (-128)) / (0 - (-4)) = 32
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the equation of the secant line through the two points (-4,-128) and (0,0)
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y = mx +b
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y = 32x +b
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pick one of the points
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0 = 32(0) + b
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b = 0
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y = 32x is the equation of the secant line
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