SOLUTION: For two consecutive integers, the smaller plus 3 times the larger is 39. Find the integers.

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Question 1139363: For two consecutive integers, the smaller plus 3 times the larger is 39. Find the integers.

Found 2 solutions by Theo, ikleyn:
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
let x equal the smaller number.
then x + 1 equals the larger number, since they are consecutive.

their sum if 39 leads to x + x + 1 = 39

subtract 1 from both sides of this equation and combine like terms to gert 2x = 38.

solve for x to get x = 38 / 2 = 19.

your solution is that the two consecutive numbers are 19 and 20.

their sum is 39.


Answer by ikleyn(52915) About Me  (Show Source):
You can put this solution on YOUR website!
.
For two consecutive integers, the smaller plus 3 times the larger is 39. Find the integers.
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Let x be the smaller of the two consecutive integers;  then  (x+1) is the larger.


The equation then is


    x + 3*(x +1) = 39.


    x + 3x + 3 = 39.

    4x         = 39 - 3

    4x         = 36

     x         = 36/4 = 9.      


ANSWER.  The integers are 9 and 10.

Completed, answered and solved.


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The tutor @Theo misread the problem and produced incorrect answer.