SOLUTION: if log 2 = 0,301 and log 3 = 0,477 solve the following showing the steps 1. 2log12 - 3log6 + 2 log 24 2. 2log12 - 4log6 + 2log24

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: if log 2 = 0,301 and log 3 = 0,477 solve the following showing the steps 1. 2log12 - 3log6 + 2 log 24 2. 2log12 - 4log6 + 2log24      Log On


   

Question 1139211: if log 2 = 0,301 and log 3 = 0,477 solve the following showing the steps
1. 2log12 - 3log6 + 2 log 24
2. 2log12 - 4log6 + 2log24
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
if log+%282%29+=+0.301 and log%28+3%29+=+0.477
solve the following showing the steps
1.
+2log%2812%29+-+3log%286%29+%2B+2log%2824%29
=+2log%28%282%5E2%2A3%29%29+-+3log%28%282%2A3%29%29+%2B+2log%28%282%5E3%2A3%29%29
=
=
=+4log%282%29%2B2log%283%29+-+3log%282%29-3log%283%29+%2B+6log%282%29%2B2log%283%29
=+7log%282%29%2Blog%283%29+.....plug in given values log+%282%29+=+0.301 and log%28+3%29+=+0.477
=+7%280.301%29%2B0.477
=+2.584

or, you can do it this way:
+2log%2812%29+-+3log%286%29+%2B+2log%2824%29
=+log%2812%5E2%29+-+log%286%5E3%29+%2B+log%2824%5E2%29
=+log%28%2812%2A12%29%29+-+log%28%286%2A6%2A6%29%29+%2B+log%28%2824%2A24%29%29
=+log%28%28%2812%2A12%29%2F%286%2A6%2A6%29%29%2824%2A24%29%29............simplify
=+log%28%282%2A2%29%2Fcross%286%29%2A%28cross%2824%294%2A24%29%29
=+log%28%282%2A2%2A2%5E2%2A2%5E3%2A3%29%29
=+log%28%282%5E7%2A3%29%29
=+log%28%282%5E7%29%29%2Blog%28%283%29%29
=+7log%282%29%2Blog%283%29
=+7%280.301%29%2B0.477
=+2.584