SOLUTION: If Dylan has 12 nickels and quarters in his pocket, and they have a combined value of 220 cents, how many of each coin does he have?

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Question 1139186: If Dylan has 12 nickels and quarters in his pocket, and they have a combined value of 220 cents, how many of each coin does he have?
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Using algebra...

q = # of quarters
n = number of nickels

q%2Bn+=+12 there are 12 coins total
25q%2B5n+=+220 the total value of the coins is 220 cents

Solve by whatever method you want....
Elimination looks easiest -- multiply the first equation by -5 and add the resulting equation to the second equation, eliminating n; then go from there.

Using logical reasoning and simple mental arithmetic...

(1) If all 12 coins were quarters, the total would be 12*25 = 300 cents; that is (300-220) = 80 cents more than the actual total.
(2) Exchanging one of the quarters for a nickel keeps the total number of coins at 12 and decreases the total value by (25-5) = 20 cents.
(3) You have to do that 80/20 = 4 times to get the total down to the correct 220 cents.

ANSWER: 4 nickels and 8 quarters