SOLUTION: if log 2 = 0,301 and log 3 = 0,477 solve the following: 2log6 + log12 - log6
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Question 1139150
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if log 2 = 0,301 and log 3 = 0,477 solve the following:
2log6 + log12 - log6
Answer by
Boreal(15235)
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2log6=2*(log3+log2)=2(0.778)=1.556
log 12=2 log 2+log 3, which is log 4+log 3=1.079
log 6 is 0.778
The result is 1.857