Question 1139136: I have figured out everything else but the p-value. I would like to know the correct steps in order to proceed with the rest of the problem.
A simple random sample of
42
men from a normally distributed population results in a standard deviation of
11.1
beats per minute. The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute. If the range rule of thumb is applied to that normal range, the result is a standard deviation of
10
beats per minute. Use the sample results with a
0.05
significance level to test the claim that pulse rates of men have a standard deviation equal to
10
beats per minute. Complete parts (a) through (d) below.
a. Identify the null and alternative hypotheses. Choose the correct answer below.
A.
Upper H 0 : sigma equals 10H0: σ=10
beats per minute
Upper H 1 : sigma not equals 10H1: σ≠10
beats per minuteYour answer is correct.
B.
Upper H 0 : sigma greater than or equals 10H0: σ≥10
beats per minute
Upper H 1 : sigma less than 10H1: σ<10
beats per minute
C.
Upper H 0 : sigma equals 10H0: σ=10
beats per minute
Upper H 1 : sigma less than 10H1: σ<10
beats per minute
D.
Upper H 0 : sigma not equals 10H0: σ≠10
beats per minute
Upper H 1 : sigma equals 10H1: σ=10
beats per minute
b. Compute the test statistic.
chi squaredχ2equals=50.516
(Round to three decimal places as needed.)
c. Find the P-value.
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! The sample size is 42, therefore
:
Degrees of Freedom(DF) = 42 - 1 = 41
:
Use chi-squared statistic you calculated - I think it is 50.516
:
Now you can look up the p-value using the chi-squared table of values or a p-value calculator
:
p-value = 0.146528
:
Since 0.146528 > 0.05, we accept the null hypothesis
:
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