SOLUTION: log base3 (x+2)+log base3(x-3)=4
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Question 1139093
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log base3 (x+2)+log base3(x-3)=4
Answer by
ankor@dixie-net.com(22740)
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adding logs is multiply
FOIL
The exponent equiv
x^2-x-6 =
x^2 - x - 6 = 81
x^2 - x - 6 - 81 = 0
x^2 - x - 87 = 0
use the quadratic formula; a=1; b=-1; c=-87
the positive solution only
x = 9.841