SOLUTION: Determine the first three terms in the binomial expansion of (x-2y)^12

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Question 1139069: Determine the first three terms in the binomial expansion of (x-2y)^12
Answer by rothauserc(4718) About Me  (Show Source):
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(x-2y)^12
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The powers on each term in the expansion always add up to 12, and that the terms counted up from zero to 12. Note nCk = n!/(k! * (n-k)!)
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The first three terms are
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12C0(x)^(12 - 0)( - 2y)^0 + 12C1(x)^(12-1)( - 2y)^1 + 12C2(x)^(12-2)( - 2y)^2 =
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x^12 -24(x)^11(y) +264(x)^10(y)^2
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