SOLUTION: A school did a survey for a month, they found out that 56% of students buy milk and 32% buy fruit everyday. If 22% of student buy both milk and fruit, what is the percentage of stu

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A school did a survey for a month, they found out that 56% of students buy milk and 32% buy fruit everyday. If 22% of student buy both milk and fruit, what is the percentage of stu      Log On


   

Question 1138862: A school did a survey for a month, they found out that 56% of students buy milk and 32% buy fruit everyday. If 22% of student buy both milk and fruit, what is the percentage of students that buy neither.
Answer by ikleyn(52879) About Me  (Show Source):
You can put this solution on YOUR website!
.

            This problem is to be solved in two steps.


Step 1.   Find the percentage of those who buys some of these two products. 

    It is  56% + 32% - 22% = 66%.


    In this formula, it should be clear to you why I added  56% and 32%.

    why I subtracted 22% ?  - Because when I added, I counted TWICE those who buys both products.


    Step 1 is completed.


STEP 2.   Find the percentage of students that buy neither. 

    It is simply complement of 66% to 100%, and it is equal to


        100% - 66% = 34%.


    It is your final answer.

Solved.