SOLUTION: In the lab, Brian has two solutions that contain alcohol and is mixing them with each other. Solution A is 7% alcohol and Solution B is 2% alcohol. He uses 200 milliliters of Sol

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Question 1138823: In the lab, Brian has two solutions that contain alcohol and is mixing them with each other. Solution A is 7% alcohol and Solution B is 2% alcohol. He uses 200
milliliters of Solution A. How many milliliters of Solution B does he use, if the resulting mixture is a 4% alcohol solution?
Answer by ikleyn(52814) About Me  (Show Source):
You can put this solution on YOUR website!
.
0.07*200 + 0.02*x = 0.04*(200+x)


x = %280.07%2A200+-+0.04%2A200%29%2F%280.04-0.02%29 = 300.


ANSWER.  300 mL of the solution B.


CHECK.   %280.07%2A200%2B0.02%2A300%29%2F%28200%2B300%29 = 0.04 = 4% concentration of the resulting mixture.   ! Correct !

Solved.

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It is a standard and typical mixture word problem.

There is entire bunch of introductory lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
in this site.

You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at the different levels of detalization, from very detailed to very short.

Read them and become an expert in solution mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.