SOLUTION: Two dice are rolled. Find the probability of rolling a sum greater than 6. Show your work in determining the answer.

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Question 1138816: Two dice are rolled. Find the probability of rolling a sum greater than 6. Show your work in
determining the answer.

Answer by ikleyn(52925) About Me  (Show Source):
You can put this solution on YOUR website!
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The full space of events is the set of all pairs  (i,j), where i and j are integer numbers from 1 to 6, inclusively.

This space consists of  6*6 = 36 elements, and each element/event has the probability of  1%2F36.


Of them, the outcomes where the sum is greater than 6, are


    sum  7 :  (1,6), (2,5), (3,4), (4,3), (5,2), (6,1)     In all, 6 pairs.

    sum  8 :  (2,6), (3,5), (4,4), (5,3), (6,2)            In all, 5 pairs.

    sum  9 :  (3,6), (4,5), (5,4), (6,3)                   In all, 4 pairs.

    sum 10 :  (4,6), (5,5), (6,4)                          In all, 3 pairs.

    sum 11 :  (5,6), (6,5)                                 In all, 2 pairs.

    sum 12 :  (6,6)                                        Only    1 pair.


Thus the number of events where the sum is greater than 6 is  6 + 5 + 4 + 3 + 2 + 1 = 21.


Therefore, the probability under the question is  21%2F36 = 7%2F12.    ANSWER

Solved.

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To see similar solved problem,  look into my lesson
    - Rolling a pair of fair dice
in this site.


Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic  "Solved problems on Probability".


Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.