SOLUTION: Ana is 24 years older than twice the age of her younger sister. In ten years, their combined ages will be 110 years. How old are they now?
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-> SOLUTION: Ana is 24 years older than twice the age of her younger sister. In ten years, their combined ages will be 110 years. How old are they now?
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You can put this solution on YOUR website! Write an expression/equation for what it says:
:
Ana is 24 years older than twice the age of her younger sister.
A = 2S + 24
:
In ten years, their ages:
(A + 10)
and
(S+10)
:
In 10 years their combined ages will be 110 years.
(A+10) + (S+10) = 110
A + 10 = 110 - S - 10
A = 110 - S - 10 - 10
A = 90 - S
:
(How old are they now?
From the 1st equation, substitute (2S+24)for A in the above equation:
2S + 24 = 90 - S
2s + S = 90 - 24
3s = 66
S = 66/3
S = 22 yrs is the sisters age
:
A = 2S + 24
A = 2(22) + 24
A = 44 + 24
A = 68 yrs is Ana's age
:
Check solution using the statement:
"In ten years, their combined ages will be 110 years"
(68 + 10) + (22 + 10) = 110
:
Could follow this OK? Any questions?
