SOLUTION: About how many times more intense is an earthquake that measures 8.6 on the Richter scale than an earthquake that measures 7.7 on the Richter scale? Recall that Richter defined the

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Question 1138534: About how many times more intense is an earthquake that measures 8.6 on the Richter scale than an earthquake that measures 7.7 on the Richter scale? Recall that Richter defined the magnitude R of an earthquake of intensity I to be R = log I. (Round your answer to two decimal places.)
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
magnitude R = log(intensity I).

8.6 = log(I) if and only if 10^8.6 = I.

7.7 = log(I) if and only if 10^7.7 = I.

divide 10^8.6 by 10^7.7 to get 10^(8.6 - 7.7) = 10^.9 = 7.943282347.

the earthquake with magnitude of 8.6 on the richter scale is 7.943282347 times the intensity of the earthquake of 7.7 on the richter scale.