SOLUTION: A bus travelling 200km has 10 stages at equal interval. The speed of the bus in the various stages was observed to be 10,15,20,25,20,30,40,50,30,40 per hour. Find the average speed

Algebra ->  Average -> SOLUTION: A bus travelling 200km has 10 stages at equal interval. The speed of the bus in the various stages was observed to be 10,15,20,25,20,30,40,50,30,40 per hour. Find the average speed      Log On


   



Question 1138422: A bus travelling 200km has 10 stages at equal interval. The speed of the bus in the various stages was observed to be 10,15,20,25,20,30,40,50,30,40 per hour. Find the average speed at which the bus travels?
Answer by ikleyn(52824) About Me  (Show Source):
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A bus travelling 200 km has 10 stages at equal highlight%28cross%28interval%29%29 lengths.
The speed of the bus in the various stages was observed to be 10, 15, 20, 25, 20, 30, 40, 50, 30, 40 highlight%28kilometers%29 per hour.
Find the average speed at which the bus travels?
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Each interval is  200%2F10 = 20 kilometers long and the time for each interval is

    20%2F10  hours  for the 1-st interval

    20%2F15  hours  for the 2-nd interval

    20%2F20  hours  for the 3-rd interval

    20%2F25  hours  for the 4-rd interval

      .  .  .  .  and so on  .  .  .  . 


So, the total time is


    Total time =  = 


        the common denominator is  600;  so, I am continuing 


    =  = 


    20%2A%28%2820+%2B+40+%2B+30+%2B+24+%2B+30+%2B+20+%2B+15+%2B+12+%2B+20+%2B+15%29%2F600%29 = 20%2A%28226%2F600%29 = 226%2F30 hours.


Then the average speed = total_distance%2Ftotal_time = 200%2F%28%28226%2F30%29%29 = %28200%2A30%29%2F226 = %28100%2A30%29%2F113 = 3000%2F113 = 23.077 kilometers per hour.       ANSWER

Solved and completed.