SOLUTION: Find an equation of the parabola that has vertex (1,2) and focus (-1,2). I think that you either use {{{(x-h)^2=4p(y-k)}}} or {{{(y-k)^2+4p(x-h)}}}, but I dont know which one to

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Find an equation of the parabola that has vertex (1,2) and focus (-1,2). I think that you either use {{{(x-h)^2=4p(y-k)}}} or {{{(y-k)^2+4p(x-h)}}}, but I dont know which one to       Log On


   



Question 113831: Find an equation of the parabola that has vertex (1,2) and focus (-1,2).
I think that you either use %28x-h%29%5E2=4p%28y-k%29 or %28y-k%29%5E2%2B4p%28x-h%29, but I dont know which one to use or how you can determine which to use. I would really appreciate it if someone could help me out. Thanks in advanced:)

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
the vertex and the focus have the same y coordinate (2) ___ this means that the axis of symmetry is parallel to the x-axis

use the second equation (with an equal sign, not a plus)