SOLUTION: a chef is going to use a mixture of two brands of italian dressing. the first brand contains 9% vinegar, and the second brand contains 14% vinegar. The chef wants to make 310 mil
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Question 1138294: a chef is going to use a mixture of two brands of italian dressing. the first brand contains 9% vinegar, and the second brand contains 14% vinegar. The chef wants to make 310 milliliters of a dressing that is 13% vinegar. How much of each brand should she use? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39618) (Show Source):
In this problem, concentrations are the ratios of the pure vinegar volume to the total volume.
Let x be the amount of the 9% vinegar needed (in milliliters), and
let y be the amount of the 14% vinegar needed.
The amount of the "pure" vinegar in the 9% mixture is 0.09x mL.
The amount of the "pure" vinegar in the 14% mixture is 0.14y mL.
The resulting mixture contains 0.09x + 0.14y mL of the pure vinegar and has the volume of 310 mL.
Thus you have these two equations
x + y = 310 milliliters (1) (the total volume)
= 0.13. (2) (the resulting mixture concentration)
From equation (1), express x = 310 - y. Substitute it into equation (2) and multiply both sides of this equation by 310.
You will get
0.09*(310-y) + 0.14y = 0.13*310.
From the last equation express y and calculate
y = = 248 mL of the 14% vinegar are needed.
Then from equation (1), x = 310 - 248 = 62 mL of the 9% vinegar are needed.
Answer. 248 mL of the 14% vinegar and 62 mL of the 9% vinegar are needed.
Check. = 0.13 = 13%. ! Correct concentration !
The problem is just solved.
I used 2-equation setup and the Substitution method.
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