SOLUTION: suppose 9 quarters, 7 dimes, 6 nickels, and 8 pennies are in a box. one coin is selected at random. what is the expected value of this experiment?
Algebra ->
Probability-and-statistics
-> SOLUTION: suppose 9 quarters, 7 dimes, 6 nickels, and 8 pennies are in a box. one coin is selected at random. what is the expected value of this experiment?
Log On
Question 1138211: suppose 9 quarters, 7 dimes, 6 nickels, and 8 pennies are in a box. one coin is selected at random. what is the expected value of this experiment? Answer by ikleyn(52866) (Show Source):
9 + 7 + 6 + 8 = 30 coins, in all.
The probability to randomly select a quarter is ;
The probability to randomly select a dime is ;
. . . . and so on . . . .
The expected value of the experiment is
= = = = 11.1 cents. ANSWER
