SOLUTION: What is the length of the period for the following equation: y+1=3cos(pi/4)(x-2). Make sure to show work.

Algebra ->  Trigonometry-basics -> SOLUTION: What is the length of the period for the following equation: y+1=3cos(pi/4)(x-2). Make sure to show work.      Log On


   

Question 1138152: What is the length of the period for the following equation: y+1=3cos(pi/4)(x-2).
Make sure to show work.
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


y+=+a%2Acos%28b%28x-c%29%29%2Bd

a is the amplitude
b determines the period: b = 2pi/period
c is the phase (horizontal) shift
d is the vertical shift

The given equation, in that form, is

y+=+3%2Acos%28%28pi%2F4%29%28x-2%29%29-1

The period is determined by b; b = 2pi/period. Since b = pi/4, the period is

2pi%2F%28pi%2F4%29 = 8