SOLUTION: Twice the square of a positive integer is 12 more than 10 times that integer. What is the integer? 10(x)^2 = x + 12 I know I have to have a formula first. Am I on the rig

Algebra ->  Real-numbers -> SOLUTION: Twice the square of a positive integer is 12 more than 10 times that integer. What is the integer? 10(x)^2 = x + 12 I know I have to have a formula first. Am I on the rig      Log On


   

Question 113814: Twice the square of a positive integer is 12 more than 10 times that integer. What is the integer?
10(x)^2 = x + 12

I know I have to have a formula first. Am I on the right track for the formula in order to solve this problem?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
2x%5E2+=+10x+%2B+12
divide both sides by 2
x%5E2+=+5x+%2B+6
x%5E2+-+5x+-+6+=+0
%28x+-+6%29%28x+%2B+1%29+=+0
x+=+6
x+=+-1 reject this- problem says POSITIVE integer
check:
2x%5E2+=+10x+%2B+12
2%2A6%5E2+=+10%2A6+%2B+12
72+=+60+%2B+12
72+=+72
OK