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Question 1138041:
Found 2 solutions by MathLover1, greenestamps:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
find log%28x%2C135%2F98%29
given:
log%28x%2C2%29=0.2702
log%28x%2C3%29=0.4283
log%28x%2C5%29=0.6275
log%28x%2C7%29=0.7587


log%28x%2C135%2F98%29
=log%28x%2C135%29-log%28x%2C98%29
=log%28x%2C135%29-log%28x%2C98%29........write 135+=+3%5E3%2A5+ and 98+=+2%2A7%5E2
=log%28x%2C3%5E3%2A5%29-log%28x%2C2%2A7%5E2%29
=log%28x%2C3%5E3%29%2Blog%28x%2C5%29-%28log%28x%2C2%29%2Blog%28x%2C7%5E2%29%29
=3log%28x%2C3%29%2Blog%28x%2C5%29-%28log%28x%2C2%29%2B2log%28x%2C7%29%29
=3log%28x%2C3%29%2Blog%28x%2C5%29-log%28x%2C2%29-2log%28x%2C7%29......plug in given values
=3%2A0.4283%2B0.6275-0.2702-2%2A0.7587
=1.2849%2B0.6275-0.2702-1.5174
=0.1248

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


All the logs are base x; so I won't show the base....

log(135/98) =
log(135)-log(98) =
log(27*5)-log(49*2) =
log(27)+log(5)-log(49)-log(2) =
log(3^3)+log(5)-log(7^2)-log(2) =
3log(3)+log(5)-2log(7)-log(2) =
3(0.4283)+0.6275-2(0.7587)-0.2702 = 0.1248