SOLUTION: 1. George has $700 to invest. Suppose he invests $300 at 6% interest. At what rate must he invest the other $400 so that the two investments yield more than $70 of yearly interest?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: 1. George has $700 to invest. Suppose he invests $300 at 6% interest. At what rate must he invest the other $400 so that the two investments yield more than $70 of yearly interest?      Log On


   



Question 1137893: 1. George has $700 to invest. Suppose he invests $300 at 6% interest. At what rate must he invest the other $400 so that the two investments yield more than $70 of yearly interest?

2. Angie bought some golf balls for $5. If each ball had cost $0.25 less, she could have purchased one more ball for the same amount of money. How many balls did Angie buy?

Found 2 solutions by VFBundy, MathTherapy:
Answer by VFBundy(438) About Me  (Show Source):
You can put this solution on YOUR website!
1. George has $700 to invest. Suppose he invests $300 at 6% interest. At what rate must he invest the other $400 so that the two investments yield more than $70 of yearly interest?

6% interest rate:
Principal = 300
Rate = 0.06
Interest = 300 * 0.06 = 18

Other interest rate:
Principal = 400
Rate = 52/400 = 0.13
Interest = 70 - 18 = 52

To yield MORE than $70 worth of interest, the $400 must be invested at a rate HIGHER than 13%.

2. Angie bought some golf balls for $5. If each ball had cost $0.25 less, she could have purchased one more ball for the same amount of money. How many balls did Angie buy?

c = cost of each ball
n = number of balls

c * n = 5
(c - 0.25) * (n + 1) = 5

This means:
c * n = (c - 0.25) * (n + 1)

Simplify:
cn = cn - 0.25n + c - 0.25

Solve for c:
0 = c - 0.25n - 0.25

c = 0.25n + 0.25

From earlier, we know:
c * n = 5

Substitute 0.25n + 0.25 for c:
c * n = 5

(0.25n + 0.25) * n = 5

Solve for n:
0.25n² + 0.25n = 5

0.25n² + 0.25n - 5 = 0

Use quadratic formula.
n+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

You will find that n = 4 and n = -5. Since the number of balls purchased cannot be a negative number, you can throw out n = -5. We are left with n = 4.

We now know Angie bought 4 balls.

From earlier:
c * n = 5

Substitute '4' for n:
c * 4 = 5

Solving for c, we find that c = 1.25.

In summary, Angie bought four balls at $1.25 apiece. (Had each ball been $0.25 cheaper, she could've bought five balls at $1.00 apiece.)

Answer by MathTherapy(10549) About Me  (Show Source):
You can put this solution on YOUR website!
1. George has $700 to invest. Suppose he invests $300 at 6% interest. At what rate must he invest the other $400 so that the two investments yield more than $70 of yearly interest?

2. Angie bought some golf balls for $5. If each ball had cost $0.25 less, she could have purchased one more ball for the same amount of money. How many balls did Angie buy?
1.
Let rate be r
The we get: .06(300) + r(400) > 70
18 + 400r > 70
400r > 52
Rate, or
2.
Let number she bought be G
Cost of each ball: 5%2FG
Had each cost 25c less, then each would be 5%2FG+-+.25
We then get: matrix%281%2C3%2C+%285%2FG+-+.25%29%28G+%2B+1%29%2C+%22=%22%2C+5%29
matrix%281%2C3%2C+5+%2B+5%2FG+-+.25G+-+.25%2C+%22=%22%2C+5%29 ------ FOILing binomials on left side
matrix%281%2C3%2C+5%2FG+-+.25G+-+.25%2C+%22=%22%2C+0%29
matrix%281%2C3%2C+5+-+.25G%5E2+-+.25G%2C+%22=%22%2C+0%29 ------- Multiplying by LCD, G
matrix%281%2C3%2C+-+.25G%5E2+-+.25G+%2B+5%2C+%22=%22%2C+0%29
matrix%281%2C3%2C+G%5E2+%2B+G+-+20%2C+%22=%22%2C+0%29 ------- Multiplying by - 4 to clear DECIMALS
(G - 4)(G + 5) = 0 --- Factoring TRINOMIAL on left side
Number of golf balls purchased, or highlight_green%28matrix%281%2C3%2C+G%2C+%22=%22%2C+4%29%29 OR G = - 5 (ignore)