SOLUTION: determine the coefficient of x^9 y^4 in the binomial expansion of (x + y)^13 power

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Question 1137744: determine the coefficient of x^9 y^4 in the binomial expansion of (x + y)^13 power
Found 3 solutions by MathLover1, MathTherapy, greenestamps:
Answer by MathLover1(20850) About Me  (Show Source):
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%28x+%2B+y%29%5E13+=13C0%2Ax%5E13%2Ay%5E0%2B13C1%2Ax%5E12%2Ay%5E1%2B13C2%2Ax%5E11%2Ay%5E2+13C3+%28x%29%5E10%2A%28y%29%5E3%2B13C4+%28x%29%5E9%2A%28y%29%5E4...
=>13C4+%28x%29%5E9%2Ay%5E4=715x%5E9%2Ay%5E4

the coefficient of x%5E9%2A+y%5E4 in the binomial expansion of %28x+%2B+y%29%5E13+power is 715

Answer by MathTherapy(10555) About Me  (Show Source):
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determine the coefficient of x^9 y^4 in the binomial expansion of (x + y)^13 power
In the BINOMIAL EXPANSION of %28x+%2B+y%29%5E13, x9y9 occurs at the term where: 
As such, 9 = 13 - (r - 1) OR 4 = r - 1
9 = 13 - r + 1 5 = r
9 - 14 = - r
- 5 = - r
5 = r
With the coefficients on x and y in %28x+%2B+y%29%5E13 being 1, the coefficient on the 5th term, when expanded, will be the value in the 5th COLUMN of the 13th ROW of Pascal’s triangle, which is highlight_green%28715%29
OR
With the coefficient on x and y being 1, the coefficient on the 5th term will be:
FYI: The entire EXPANSION DOESN'T HAVE to be done, as one person decided to do!
What if x%5E9y%5E4 was the 24th or 25th term of the expansion? Do you think it'd be wise to do the entire expansion? Think about it!

Answer by greenestamps(13203) About Me  (Show Source):
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Since the coefficients of x and y are both 1, the coefficient of the x^9y^4 term in the expansion of (x+y)^13 is

C%2813%2C4%29%281%5E9%29%281%5E4%29+=+c%2813%2C4%29+=+715