SOLUTION: A rabbit population rises and falls each year. It is at a minimum of 4000 rabbits in January and a maximum of 4600 rabbits six months later. By the following January the population

Algebra ->  Trigonometry-basics -> SOLUTION: A rabbit population rises and falls each year. It is at a minimum of 4000 rabbits in January and a maximum of 4600 rabbits six months later. By the following January the population      Log On


   

Question 1137712: A rabbit population rises and falls each year. It is at a minimum of 4000 rabbits in January and a maximum of 4600 rabbits six months later. By the following January the population drops again to 4000 rabbits. Let P(t) model the number of rabbits in the population where t is the number of months since January. (Suppose when t=0 that it is the first January.)
P(t)=Acos(Bt)+C

Answer by ikleyn(52800) About Me  (Show Source):
You can put this solution on YOUR website!
.
P(t) = -300%2Acos%282pi%2A%28t%2F12%29%29+%2B+4300,


t is the sequential number of the month in the year, starting from  t = 0  for January.


A = -300 (300 is the amplitude);  B = %282pi%2F12%29;  C = 4300 - the average value per year.