SOLUTION: At noon a private plane left Austin for Los Angeles,2100km away, flying at 500km/h. One hour later a jet left Los Angeles for Austin at 700km/h. At what time did they pass each oth
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: At noon a private plane left Austin for Los Angeles,2100km away, flying at 500km/h. One hour later a jet left Los Angeles for Austin at 700km/h. At what time did they pass each oth
Log On
Question 113760This question is from textbook Algebra Structure and method
: At noon a private plane left Austin for Los Angeles,2100km away, flying at 500km/h. One hour later a jet left Los Angeles for Austin at 700km/h. At what time did they pass each other?
Here is what I have so far.I am not sure how to do this
2100=500(t+60)-700(t-60) This question is from textbook Algebra Structure and method
You can put this solution on YOUR website! At noon a private plane left Austin for Los Angeles,2100km away, flying at 500km/h. One hour later a jet left Los Angeles for Austin at 700km/h. At what time did they pass each other?
-----------------------------
Private plane DATA:
Rate = 500 km/h ; time = x hrs; distance = 500x km
-----------
Jet DATA:
Rate = 700 km/h ; time = x-1 hrs ; distance = 700(x-1)
--------------
EQUATION:
private distance + jet distance = 2100 km
500x + 700(x-1) = 2100
5x + 7x-7 = 21
12x = 28
x= 7/3 hrs = 2 hrs 20 minutes
------------
They passed at noon + 2 hrs 20 min or 2:20 PM
=====================
Cheers,
Stan H.
(