Question 1137499: Using long division, find the quotient and remainder (if any).
3x^4-4x^2+4x+8/ x+1 Found 2 solutions by josgarithmetic, MathLover1:Answer by josgarithmetic(39627) (Show Source):
First ask, what is ?
That is . After that you do what you normally do in long division...
3x^3
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x+1 | 3x^4 0x^3 -4x^2 4x 8
|
|
3x^3 -3x^2 -x 5
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x+1 | 3x^4 0x^3 -4x^2 4x 8
|
| 3x^4 3x^3
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0 -3x^3 -4x^2
-3x^3 -3x^2
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0 -x^2 4x
-x^2 -x
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5x 8
5x 5
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3
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