SOLUTION: y varies jointly as x and the square of z and inversely as the cube of w. If when x=3, z=4, and w=2, y=48, what is y when x=4, z=5, and w=3?

Algebra ->  Rational-functions -> SOLUTION: y varies jointly as x and the square of z and inversely as the cube of w. If when x=3, z=4, and w=2, y=48, what is y when x=4, z=5, and w=3?      Log On


   

Question 1137497: y varies jointly as x and the square of z and inversely as the cube of w. If when x=3, z=4, and w=2, y=48, what is y when x=4, z=5, and w=3?
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
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y varies jointly as x and the square of z and inversely as the cube of w.
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You can figure out the rest.