SOLUTION: kindly solve these question:
solve the inequality and represent the solution on number line:
1: (x+8)/(12)<(x-1)/(10)
2: (2x)/(x+2)>=(x)/(x-2)
3: (x^2-x+1)>1
thank you
Algebra ->
Inequalities
-> SOLUTION: kindly solve these question:
solve the inequality and represent the solution on number line:
1: (x+8)/(12)<(x-1)/(10)
2: (2x)/(x+2)>=(x)/(x-2)
3: (x^2-x+1)>1
thank you
Log On
Question 1137484: kindly solve these question:
solve the inequality and represent the solution on number line:
1: (x+8)/(12)<(x-1)/(10)
2: (2x)/(x+2)>=(x)/(x-2)
3: (x^2-x+1)>1
thank you Answer by ikleyn(52835) (Show Source):
1: <
Multiply both sides of the inequality by 120 to get
10*(x+8) < 12*(x-1)
10x + 80 < 12x - 12
80 + 12 < 12x - 10x
92 < 2x
Divide both sides by 2 to get the ANSWER : x > 46.
3. x^2 - x + 1 > 1
It is equivalent to
x^2 - x > 0
x*(x-1) > 0
Case a): both factors are positive : x > 0 and x-1 > 0.
The set of solutions is { x > 1}.
Case b): both factors are negative : x < 0 and x-1 < 0.
The solution set is x < 0.
ANSWER. The solution set for the given inequality is the union of two semi-infinite intervals (,) U (,).