SOLUTION: kindly solve these question: solve the inequality and represent the solution on number line: 1: (x+8)/(12)<(x-1)/(10) 2: (2x)/(x+2)>=(x)/(x-2) 3: (x^2-x+1)>1 thank you

Algebra ->  Inequalities -> SOLUTION: kindly solve these question: solve the inequality and represent the solution on number line: 1: (x+8)/(12)<(x-1)/(10) 2: (2x)/(x+2)>=(x)/(x-2) 3: (x^2-x+1)>1 thank you      Log On


   



Question 1137484: kindly solve these question:
solve the inequality and represent the solution on number line:
1: (x+8)/(12)<(x-1)/(10)
2: (2x)/(x+2)>=(x)/(x-2)
3: (x^2-x+1)>1
thank you

Answer by ikleyn(52835) About Me  (Show Source):
You can put this solution on YOUR website!
.
1:  %28x%2B8%29%2F12 < %28x-1%29%2F10


    Multiply both sides of the inequality by 120 to get


    10*(x+8) < 12*(x-1)

    10x + 80 < 12x - 12

    80 + 12 < 12x - 10x

    92 < 2x


     Divide both sides by 2 to get the  ANSWER :  x > 46.




3.  x^2 - x + 1 > 1


    It is equivalent to


    x^2 - x > 0

    x*(x-1) > 0


    Case a):  both factors are positive :  x > 0 and x-1 > 0.

              The set of solutions is  { x > 1}.



    Case b):  both factors are negative :  x < 0  and x-1 < 0.

              The solution set is  x < 0.


ANSWER.  The solution set for the given inequality is the union of two semi-infinite intervals  (-infinity,0) U (1,infinity).


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