SOLUTION: A cone frustum is inscribed in a sphere of radius 13. If one of the bases of the frustum is a great circle of the sphere, and the other base has radius 12, what is height.

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Question 1137433: A cone frustum is inscribed in a sphere of radius 13. If one of the bases of the frustum is a great circle of the sphere, and the other base has radius 12, what is height.
Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
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The height of this frustum is equal to the distance of its smaller base from the center of the sphere.


In turn, this distance is  sqrt%2813%5E2+-+12%5E2%29 = sqrt%28169-144%29 = sqrt%2825%29 = 5.


ANSWER.  The height of the frustum is 5 units.