SOLUTION: Find all polar coordinates of point P where P = ordered pair 5 comma pi divided by 3 . (2 points) choices below 1.(7, pi divided by 3 + 2nπ) or (-7, pi divided by 3 + 2nπ)

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Question 1137303: Find all polar coordinates of point P where P = ordered pair 5 comma pi divided by 3 . (2 points) choices below

1.(7, pi divided by 3 + 2nπ) or (-7, pi divided by 3 + 2nπ)

2.(7, pi divided by 3 + 2nπ) or (-7, pi divided by 3 + (2n + 1)π)

3.(7, pi divided by 3 + (2n + 1)π) or (-7, pi divided by 3 + 2nπ)

4.(7, pi divided by 3 + nπ) or (-7, pi divided by 3 + nπ)

Found 2 solutions by Theo, ikleyn:
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
i think this one.

2.(7, pi divided by 3 + 2nπ) or (-7, pi divided by 3 + (2n + 1)π)

see my worksheet, shown below:

$$$

your base angles are:

(7, pi/3) and (-7, 4pi/3)

they can also be shown as:

(7, pi/3) and (-7, pi/3 + pi)

you are basically adding n * 360 degrees to the angle, which will make the angle always be in the same position.

the worksheet shows the angle plus 2 * pi which is the same as adding 360 degrees to it.

their selections are after the addition of n * 2 * pi to the base form have been converted to the final form which i assume they think is simplified.

it's not so simple if you don't know what they're doing or why they're doing it.

my worksheet shows the progression from the unsimplified form to the simplified form as shown in your selections.

bottom line:

go with:

2.(7, pi divided by 3 + 2nπ) or (-7, pi divided by 3 + (2n + 1)π)

pi and π mean the same thing.



Answer by ikleyn(52879) About Me  (Show Source):
You can put this solution on YOUR website!
.

            This post is a duplicate,  and  @greenestamps just answered this question couple of days ago.

            Here, I will repeat his answer.



The given point has the modulus of  5.

The option answers all are with the modulus of  7.

Therefore,  NO ONE  of the answers matches the given point.


The answer by  @Theo  is   I N C O R R R E C T.